Consider the point P = (3,8) and the line L, given by the equation y = 3x -4. A. Write an equation in slope-intercept of the line passing through P and parallel to line L.B. Write an equation in slope-intercept of the line passing through P and perpendicular to line L.

Answer:A parallel y = 3x-1B perpendicular y = -1/3x+9Step-by-step explanation:y = 3x-4 is written in slope intercept form  (y=mx+b) so the slope is 3.A.  If the lines are parallel they have the same slopem parallel is 3Using point slope formy-y1 = m(x-x1)y-8 = 3(x-3)Distributey-8 = 3x-9Add 8 to each sidey-8+8 = 3x-9+8y = 3x-1This is slope intercept formB If we want perpendicular lines, the slope is the negative reciprocalm perpendicular is -(1/3)  = -1/3Using point slope formy-y1 = m(x-x1)y-8 = -1/3(x-3)Distributey-8 = -1/3x+1Add 8 to each sidey-8+8 = -1/3x+1+8y = -1/3x+9This is slope intercept form