Write an equation in standard form of the line passing through the points (3,3) and (-3,5)

The equation of line passing through the points (3,3) and (-3,5) is:x+3y=12Step-by-step explanation:Given points are:(x1, y1) = (3,3)(x2, y2) = (-3, 5)The general form of slope-intercept form is:[tex]y=mx+b[/tex]We have to find slope first[tex]m=\frac{y_2-y_1}{x_2-x_1}\\=\frac{5-3}{-3-3}\\=\frac{2}{-6}\\=-\frac{1}{3}[/tex]Putting the value of m in general form[tex]y=-\frac{1}{3}x+b[/tex]To find the value of b, putting (3,3) in equation[tex]3=-\frac{1}{3}(3)+b\\3=-1+b\\b=4[/tex]Putting the values of m and b in general form[tex]y=-\frac{1}{3}x+4[/tex]Multiplying both sides by 3[tex]3y=-x+12\\x+3y=12[/tex]The equation of line passing through the points (3,3) and (-3,5) is:x+3y=12Keywords: Equation of line, Standard formLearn more about standard form of equation of line at:brainly.com/question/4793866brainly.com/question/4824362#LearnwithBrainly