I need help bruv. like asap. For the function y=x^2 - 5x - 6 (a) Find the vertex (b) Find the y-intercept (c) Find the x-intercepts (Leave your answers in simplified radical form or, where appropriate, round to the nearest hundredth.)

Answer:Listed belowStep-by-step explanation:This is a cuadratic function excercise. We know that cuadratic functions have the following formula: [tex]y=ax^{2} +bx+c[/tex]The graphic of this function will give us a parabola, that can be graphed knowing four points: the two or less x-intercepts, the y-intercept, and the vertex (Xv;Yv). A) The vertexThe vertex is a point on the graph, so we have to know it's value on the X axis and on the Y axis. To know the value of Xv we can calculate it using the following formula:[tex]Xv=\frac{-b}{2a}[/tex]We know that in this case: [tex]a=1\\b=-5\\c=-6[/tex]So we supplant said values on the formula and we get: [tex]Xv=\frac{-(-5)}{2.1} =\frac{5}{2}=2.5[/tex]To know the value of Yv, we suppland the value of Xv on the function's formula. [tex]f(x=\frac{-5}{2})=(\frac{-5}{2}) ^{2} -5.\frac{-5}{2}-6=\frac{51}{4}=12.75[/tex]So we know now that [tex]Xv=\frac{-5}{2}[/tex] and [tex]Yv=\frac{51}{4}[/tex]b) The y-intercept is the value of C on the function's formula. We know that c=-6, so[tex]Y=-6[/tex]c) The x-intercepts can be resolved using the following formula:[tex]x=\frac{-b+-\sqrt[2]{b^{2}-4ac}  }{2a} \\\\x=\frac{-5+-\sqrt[2]{(-5)^{2}-4.1.(-6)}  }{2.1} \\x=\frac{-(-5)+-\sqrt[2]{25+24}  }{2}\\x=\frac{5+-\sqrt[2]{49}  }{2.1}\\x=\frac{5+-7  }{2.1}[/tex]This means that this formula can have two posisible solutions: [tex]x= \frac{5+7}{2} =\frac{12}{2}=6[/tex]Or:[tex]x= \frac{5+7}{2} =\frac{-2}{2}=-1[/tex]So that are the X-intercepts: x=6 and x=-1